How many moles of hypomanganous acid, H3MnO4, are contained in 22.912 g?

Question

How many moles of hypomanganous acid, H3MnO4, are contained in 22.912 g?

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Dâu 6 months 2021-07-31T19:35:51+00:00 1 Answers 8 views 0

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    2021-07-31T19:37:49+00:00

    Answer:

    0.188mol

    Explanation:

    Using the formula as follows:

    mole = mass/molar mass

    Molar mass of hypomanganous acid, H3MnO4 = 1(3) + 55 + 16(4)

    = 3 + 55 + 64

    = 122g/mol

    Mass of H3MnO4 is given as 22.912 g

    Hence;

    moles = 22.912 ÷ 122

    number of moles = 0.188mol

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