How many moles are equivalent to 365 g of aluminum chloride? Using the dimensions analysis. Show work

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How many moles are equivalent to 365 g of aluminum chloride? Using the dimensions analysis. Show work

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Delwyn 4 years 2021-07-18T10:39:17+00:00 1 Answers 6 views 0

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    2021-07-18T10:40:18+00:00

    Answer:

    ≈ 2.74 mol AlCl_{3}

    (I rounded to 3 sig figs because the starting amount has 3 sig figs.)

    Explanation:

    \frac{365g   AlCl_{3}}{1}*\frac{1    mol    AlCl_{3}}{133.34g AlCl_{3}} = 2.73736313184 mol AlCl_{3} ≈ 2.74 mol AlCl_{3}

    Hope this helps!

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