How many liters of Cl2 gas will you have if you are using 63 g of Na?

Question

How many liters of Cl2 gas will you have if you are using 63 g of Na?

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Delwyn 6 months 2021-07-26T21:36:58+00:00 1 Answers 1 views 0

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    2021-07-26T21:38:08+00:00

    Answer:

    You will have 19.9L of Cl2

    Explanation:

    We can solve this question using:

    PV = nRT; V = nRT/P

    Where V is the volume of the gas

    n the moles of Cl2

    R is gas constant = 0.082atmL/molK

    T is 273.15K assuming STP conditions

    P is 1atm at STP

    The moles of 63g of Cl2 gas are -molar mass: 70.906g/mol:

    63g * (1mol / 70.906g) = 0.8885 moles

    Replacing:

    V = 0.8885mol*0.082atmL/molK*273.15K/1atm

    V = You will have 19.9L of Cl2

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )