How many liters of carbon dioxide gas are produced from 0.012 moles oxygen and excess propane at STP? 1 C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4

Question

How many liters of carbon dioxide gas are produced from 0.012 moles oxygen and excess propane at STP? 1 C3H8 (g) + 5 O2 (g) → 3 CO2 (g) + 4 H2O (g) ______ Liters CO2

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Phúc Điền 2 months 2021-07-29T14:33:47+00:00 1 Answers 2 views 0

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    2021-07-29T14:34:56+00:00

    Answer:

    0.16 L

    Explanation:

    Step 1: Write the balanced equation

    C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

    Step 2: Calculate the moles of CO₂ produced from 0.012 moles of O₂

    The molar ratio of O₂ to CO₂ is 5:3. The moles of CO₂ produced are 3/5 × 0.012 mol = 0.0072 mol.

    Step 3: Calculate the volume occupied by 0.0072 moles of CO₂ at standard temperature and pressure

    At STP, 1 mole of CO₂ occupies 22.4 L.

    0.0072 mol × 22.4 L/1 mol = 0.16 L

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