How many liters of 30% salt solution must be added to 6 L of an 80% salt solution to obtain a 50% salt solution July 20, 2021 by Doris How many liters of 30% salt solution must be added to 6 L of an 80% salt solution to obtain a 50% salt solution
Answer: 9 Liters Step-by-step explanation: Let us represent: The number of liters of the 30% salt solution = x Number of liters for the 80% solution = 6 Liters Number of liters for the 50% solution = x + 6 Liters Hence: x × 30% + 6 × 80% = (x + 6)50% 0.3x + 4.8 = 0.5x + 3 Collect like terms 4.8 – 3 = 0.5x – 0.3x 1.8 = 0.2x x = 1.8/0.2 x = 9 Liters Therefore, the number of liters for the 30% Salt solution = 9 Liters Reply
Answer:
9 Liters
Step-by-step explanation:
Let us represent:
The number of liters of the 30% salt solution = x
Number of liters for the 80% solution = 6 Liters
Number of liters for the 50% solution = x + 6 Liters
Hence:
x × 30% + 6 × 80% = (x + 6)50%
0.3x + 4.8 = 0.5x + 3
Collect like terms
4.8 – 3 = 0.5x – 0.3x
1.8 = 0.2x
x = 1.8/0.2
x = 9 Liters
Therefore, the number of liters for the 30% Salt solution = 9 Liters