How many liters of 30% salt solution must be added to 6 L of an 80% salt solution to obtain a 50% salt solution

Question

How many liters of 30% salt solution must be added to 6 L of an 80% salt solution to obtain a 50% salt solution

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Doris 6 months 2021-07-20T12:03:54+00:00 1 Answers 42 views 0

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    2021-07-20T12:05:18+00:00

    Answer:

    9 Liters

    Step-by-step explanation:

    Let us represent:

    The number of liters of the 30% salt solution = x

    Number of liters for the 80% solution = 6 Liters

    Number of liters for the 50% solution = x + 6 Liters

    Hence:

    x × 30% + 6 × 80% = (x + 6)50%

    0.3x + 4.8 = 0.5x + 3

    Collect like terms

    4.8 – 3 = 0.5x – 0.3x

    1.8 = 0.2x

    x = 1.8/0.2

    x = 9 Liters

    Therefore, the number of liters for the 30% Salt solution = 9 Liters

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