How many Joules of heat are required to heat 75g of ice from -15℃ to 235℃? -q=mCpΔT – q=mΔH – q=mCpΔT – q=mΔH – q=

Question

How many Joules of heat are required to heat 75g of ice from -15℃ to 235℃?
-q=mCpΔT
– q=mΔH
– q=mCpΔT
– q=mΔH
– q=mCpΔT
-Total Energy Joules=
-Total energy in kilojoules 1000 J = 1 kJ

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Thu Nguyệt 3 years 2021-08-01T06:56:47+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-08-01T06:57:53+00:00

    Answer:

    78000 J

    General Formulas and Concepts:

    Chemistry

    Thermodynamics

    Specific Heat Formula: q = mcΔT

    • q is heat (in J)
    • m is mass (in g)
    • c is specific heat (in J/g °C)
    • ΔT is change in temperature (in °C)

    Math

    Pre-Algebra

    Order of Operations: BPEMDAS

    1. Brackets
    2. Parenthesis
    3. Exponents
    4. Multiplication
    5. Division
    6. Addition
    7. Subtraction
    • Left to Right

    Explanation:

    Step 1: Define

    Identify variables

    [Given] m = 75 g

    [Given] c = 4.184 J/g °C

    [Given] ΔT = 235 °C – -15°C = 250 °C

    [Solve] q

    Step 2: Solve for q

    1. Substitute in variables [Specific Heat Formula]:                                             q = (75 g)(4.184 J/g °C)(250 °C)
    2. Multiply [Cancel out units]:                                                                               q = (313.8 J/°C)(250 °C)
    3. Multiply [Cancel out units]:                                                                               q = 78450 J

    Step 3: Check

    Follow sig fig rules and round. We are given 2 sig figs as our lowest.

    78450 J ≈ 78000 J

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