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How many Joules of heat are required to heat 75g of ice from -15℃ to 235℃? -q=mCpΔT – q=mΔH – q=mCpΔT – q=mΔH – q=
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Answers ( )
Answer:
78000 J
General Formulas and Concepts:
Chemistry
Thermodynamics
Specific Heat Formula: q = mcΔT
Math
Pre-Algebra
Order of Operations: BPEMDAS
Explanation:
Step 1: Define
Identify variables
[Given] m = 75 g
[Given] c = 4.184 J/g °C
[Given] ΔT = 235 °C – -15°C = 250 °C
[Solve] q
Step 2: Solve for q
Step 3: Check
Follow sig fig rules and round. We are given 2 sig figs as our lowest.
78450 J ≈ 78000 J