## how many grams of sodium azide are required to form 16.55g of nitrogen gas in 2 N a N 3 ( s

Question

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## Answers ( )

Answer:16.8128 grams of sodium azide is needed

Explanation:2NaN3 = 2Na + 3N2

molar mass of NaN3 =

molar mass of N2

moles of N2 =

moles=mass/R.F.M

16.55÷42 = 0.3940

mole ratio=

2NaN3 : 3N2

3 = 0.3940

2=?

Mass of sodium azide =64×0.2627

=16.8126