how many grams of p2o3 can be produced from 95l o2 at STP

Question

how many grams of p2o3 can be produced from 95l o2 at STP

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2 months 2021-07-22T15:59:11+00:00 1 Answers 4 views 0

1. Explanation:

Balanced Equation

P

2

O

3

+

3H

2

O

2H

3

PO

3

First use the balanced equation to determine the mole ratio between

H

3

PO

3

and

P

2

O

3

. This ratio will be used to determine the moles

P

2

O

3

required to produce

10.2

moles

H

3

PO

3

.

Mole Ratio Between

P

2

O

3

and

H

3

PO

3

from the balanced equation.

1

mol P

2

O

3

2

mol H

3

PO

3

and

2

mol H

3

PO

3

1

mol P

2

O

3

Multiply the moles

H

3

PO

3

by the molar mass that cancels

H

3

PO

3

and leaves

P

2

O

3

10.2

mol H

3

PO

3

×

1

mol P

2

O

3

2

mol H

3

PO

3

=

5.10 mol P

2

O

3

Now that the moles

P

2

O

3

required to produce

10.2 mol H

3

PO

3

are known, multiply the number of moles by its molar mass,

109.945 g/mol

. https://www.ncbi.nlm.nih.gov/pccompound?term=P2O3 This will give the mass in grams needed for

P

2

O

3

to produce

10.2 mol H

3

PO

3

.

5.10

mol P

2

O

3

×

109.945

g P

2

O

3

1

mol P

2

O

3

=

561 g P

2

O

3

rounded to three significant figures