how many grams of p2o3 can be produced from 95l o2 at STP

Question

how many grams of p2o3 can be produced from 95l o2 at STP

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Eirian 2 months 2021-07-22T15:59:11+00:00 1 Answers 4 views 0

Answers ( )

    0
    2021-07-22T16:00:16+00:00

    Explanation:

    Balanced Equation

    P

    2

    O

    3

    +

    3H

    2

    O

    2H

    3

    PO

    3

    First use the balanced equation to determine the mole ratio between

    H

    3

    PO

    3

    and

    P

    2

    O

    3

    . This ratio will be used to determine the moles

    P

    2

    O

    3

    required to produce

    10.2

    moles

    H

    3

    PO

    3

    .

    Mole Ratio Between

    P

    2

    O

    3

    and

    H

    3

    PO

    3

    from the balanced equation.

    1

    mol P

    2

    O

    3

    2

    mol H

    3

    PO

    3

    and

    2

    mol H

    3

    PO

    3

    1

    mol P

    2

    O

    3

    Multiply the moles

    H

    3

    PO

    3

    by the molar mass that cancels

    H

    3

    PO

    3

    and leaves

    P

    2

    O

    3

    10.2

    mol H

    3

    PO

    3

    ×

    1

    mol P

    2

    O

    3

    2

    mol H

    3

    PO

    3

    =

    5.10 mol P

    2

    O

    3

    Now that the moles

    P

    2

    O

    3

    required to produce

    10.2 mol H

    3

    PO

    3

    are known, multiply the number of moles by its molar mass,

    109.945 g/mol

    . https://www.ncbi.nlm.nih.gov/pccompound?term=P2O3 This will give the mass in grams needed for

    P

    2

    O

    3

    to produce

    10.2 mol H

    3

    PO

    3

    .

    5.10

    mol P

    2

    O

    3

    ×

    109.945

    g P

    2

    O

    3

    1

    mol P

    2

    O

    3

    =

    561 g P

    2

    O

    3

    rounded to three significant figures

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )