How many grams of oxygen are required to burn 13.50 grams of acetylene?

Question

How many grams of oxygen are required to burn 13.50 grams of acetylene?

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Mộc Miên 2 months 2021-07-28T22:06:13+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-07-28T22:07:17+00:00

    About
    553.6
    grams of oxygen are used in this combustion.
    Explanation:
    Molecular mass of acetylene:
    2

    M
    M
    C
    +
    2

    M
    M
    H

    M
    M
    C
    = Molecular mass of carbon
    M
    M
    H
    = Molecular mass of hydrogen
    So,
    2

    12
    +
    2

    1
    =
    26
    grams/mole
    Mass used in combustion
    molecular mass
    =
    moles used in combustion
    180
    grams
    26
    grams
    mole
    =
    6.92
    moles
    According to the main equation, to 2 moles of acetylene, 5 moles of oxygen are used.
    M
    M
    O
    =
    2

    16
    =
    32
    grams/mole
    So, if we use
    6.92
    moles of Acetylene,
    x
    moles of oxygen will be necessary.
    x
    =
    6.92

    5
    2
    =
    3.46

    5
    =
    17.3
    moles of oxygen.
    17.3
    moles

    32
    grams
    mole
    =
    553.6
    grams of oxygen

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