How many grams of glycerine, C3H8O3, are needed to make 100. mL of 2.60 M solution?

Question

How many grams of glycerine, C3H8O3, are needed to make 100. mL of 2.60 M solution?

in progress 0
Euphemia 4 years 2021-09-01T01:27:10+00:00 1 Answers 30 views 0

Answers ( )

  1. Acacia
    0
    2021-09-01T01:28:59+00:00
    Reply

    Answer:

    the mass of the glycerine needed in the given solution is  23.92 g

    Explanation:

    Given;

    molarity of the solution (C₃H₈O₃), C = 2.60 M

    Volume of the solution, V = 100 mL = 100 x 10⁻³ L = 0.1 M

    The molarity of a solution is given as follows;

    Molarity = \frac{amount \ of \ solute \ (moles)}{volume \ of \ solution \ (L)} \\\\amount \ of \ solute \ (moles) = Molarity \ \times volume \ of \ solution \ (L)\\\\amount \ of \ solute \ (moles) = 2.6 \times 0.1 \\\\amount \ of \ solute \ (moles) = 0.26 \ mole

    The molecular mass of the given solution;

    molecular mass = (12 x 3) + (8 x 1) + (16 x 3)

    molecular mass = 92 g/mol

    The mass of the glycerine needed in the given solution is calculated as follows;

    reacting mass = amount of solute (moles)   x   molecular mass (g/mol)

    reacting mass = 0.26 x 92

    reacting mass = 23.92 g

    Therefore, the mass of the glycerine needed in the given solution is  23.92 g

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )