How many grams of FeCl3 are needed to make 1.5 L of a solution with a molarity of 0.450 M?

Question

How many grams of FeCl3 are needed to make 1.5 L of a solution with a molarity of 0.450 M?

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Linh Đan 3 years 2021-07-25T19:36:35+00:00 1 Answers 6 views 0

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  1. kimchi2
    0
    2021-07-25T19:38:20+00:00
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    Moles=concentration x volume. 1.5/1000 multiply 0.450 = 6.75×10^-4
    To find the mass of fecl3, we have the formula, mass=moles x molar mass. 6.75×10^-4 x (55.8+35.5 x 3). = 0.1096g

    Not sure tho if i did it right

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