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How many grams of calcium carbonate, CaCO3, contain 48 grams of oxygen atoms? A) 41 B) 50 C) 62 D) 88 E)
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Answer:
(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =
83 g CaCO3
So answer D), although three significant digits are not justified.
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