How many grams of aluminum to complete the reactions below? Extra Content 6HCl(aq) + 2Al(s) → 2AlCl3(s) + 3H2(g) si

Question

How many grams of aluminum to complete the reactions below?

Extra Content
6HCl(aq) + 2Al(s) → 2AlCl3(s) + 3H2(g)
six moles of hydrochloric acid reacts with two moles of aluminum to produce 2 moles of aluminum chloride plus 3 moles of hydrogen gas.

A.
26.9 grams
B.
55 grams
C.
53.96 grams
D.
2 grams

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Gerda 5 months 2021-08-27T04:51:47+00:00 1 Answers 2 views 0

Answers ( )

    0
    2021-08-27T04:53:23+00:00

    The answer is option C

    Explanation:

    Al= 26.982

    2 moles of aluminium wad given so

    2× 26.982= 53.96 grams

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