How many grams are there in 1.8055 x 10^25 molecules of sodium sulfate? Hint: Convert to moles first

Question

How many grams are there in 1.8055 x 10^25 molecules of sodium sulfate? Hint: Convert to moles first

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Hưng Khoa 6 months 2021-08-25T11:29:52+00:00 1 Answers 1 views 0

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    2021-08-25T11:31:24+00:00

    Answer:

    4258.82 g of Na₂SO₄

    Explanation:

    From the question given above, the following data were obtained;

    Number of molecules of Na₂SO₄ = 1.8055×10²⁵ molecules.

    Number of mole of Na₂SO₄ =?

    From Avogadro’s hypothesis,

    6.02×10²³ molecules = 1 mole

    Therefore,

    6.02×10²³ molecules = 1 mole of Na₂SO₄

    Next, we shall determine the mass of 1 mole of Na₂SO₄. This can be obtained as follow:

    1 mole of Na₂SO₄ = (23×2) + 32 + (16×4)

    = 46 + 32 + 64

    = 142 g

    Thus,

    6.02×10²³ molecules = 142 g of Na₂SO₄

    Finally, we shall determine the mass of Na₂SO₄ that contains 1.8055×10²⁵ molecules. This can be obtained as follow:

    6.02×10²³ molecules = 142 g of Na₂SO₄

    Therefore,

    1.8055×10²⁵ molecules

    = (1.8055×10²⁵ × 142) / 6.02×10²³

    = 4258.82 g of Na₂SO₄

    Thus, 4258.82 g of Na₂SO₄ contains 1.8055×10²⁵ molecules

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