How many ATOMS of boron are present in 3.61 grams of boron trifluoride ?

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How many ATOMS of boron are present in 3.61 grams of boron trifluoride ?

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Thiên Di 7 months 2021-07-11T20:01:36+00:00 1 Answers 9 views 0

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    2021-07-11T20:03:05+00:00

    Hi there!

    \large\boxed{3.203 *  10^{22} atoms}

    We can use the following conversions to solve:

    Total mass –> amount of mols –> amount of atoms (Avogadro’s number)

    Begin by calculating the amount of boron trifluoride in 3.61 grams:

    3.61 g * (1 mol BF₃ / 67.8 g) ≈ 0.0532 mol BF₃

    Use avogadro’s number to convert:

    0.0532 mol * 6.02× 10²³atoms / 1 mol = 3.203 × 10²² atoms

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