how many atoms are present in 14 g of iron

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how many atoms are present in 14 g of iron

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Thu Thủy 2 months 2021-07-30T06:55:17+00:00 1 Answers 0 views 0

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    2021-07-30T06:56:39+00:00

    Answer:

    1.51 × 10²³ atoms

    Explanation:

    First, we convert 14g of iron (Fe) to moles using the formula below:

    mole = mass ÷ molar mass

    Molar mass of Fe = 55.85g/mol

    mole = 14g ÷ 55.85g/mol

    mole = 0.251mol

    The number of atoms in 0.251 mol of Fe is calculated as follows:

    number of atoms = n × nA

    Where;

    n = number of moles

    nA = Avagadros number (6.02 × 10²³)

    number of atoms = 0.251 × 6.02 × 10²³

    number of atoms = 1.51 × 10²³ atoms.

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