how many atoms are in a 4.7 g copper coin?​

Question

how many atoms are in a 4.7 g copper coin?​

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Thu Cúc 6 months 2021-07-17T06:25:14+00:00 2 Answers 6 views 0

Answers ( )

    0
    2021-07-17T06:26:56+00:00

    3.11 is the answer I think

    0
    2021-07-17T06:27:07+00:00

    Answer:

    x = 4.45 * 10 ^22  Note. Technically, this should be rounded to 4.5 * 10^22. There are only 2 sig digits.

    Explanation:

    You have to assume that the coin is pure copper, which I doubt.  What a coin is actually made of  depends on when it was minted. But for the sake of this question, we’ll assume coins are pure copper.

    Copper has an atomic mass of 63.546 grams / mol

    So 4.7 g of copper = 4.7 / 63.545 mol

    We have 0.07396 mol of copper

    1 mol of anything = 6.02 * 10^23 atoms (in this case).

    0.07396 mol        = x

    Cross Multiply

                   

    1 * x = 0.07396 * 6.02 * 10^23

    x = 4.45 * 10 ^22  atoms of copper

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