How many atoms are in 10.1 g Ne

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How many atoms are in 10.1 g Ne

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Edana Edana 4 years 2021-07-20T06:30:47+00:00 1 Answers 11 views 0

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    2021-07-20T06:31:52+00:00

    Answer:

    3.01 × 10²³ atoms Ne

    General Formulas and Concepts:

    Atomic Structure

    • Reading a Periodic Tables
    • Moles

    Stoichiometry

    • Using Dimensional Analysis

    Explanation:

    Step 1: Define

    Identify

    [Given] 10.1 g Ne

    [Solve] atoms Ne

    Step 2: Identify Conversions

    Avogadro’s Number – 6.022 × 10²³ atoms, molecules, formula units, etc.

    [PT] Molar Mass of Ne: 20.18 g/mol\

    Step 3: Convert

    1. [DA] Set up:                                                                                                       \displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})
    2. [DA] Divide/Multiply [Cancel out units]:                                                          \displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne

    Step 4: Check

    Follow sig fig rules and round. We are given 3 sig figs.

    3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne

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