How many 3 digits positive integers exist that when divided by 7 leave a remainder of 0

Question

How many 3 digits positive integers exist that when divided by 7 leave a remainder of 0

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Thu Giang 3 years 2021-08-26T10:21:42+00:00 2 Answers 71 views 0

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  1. Sapo1
    0
    2021-08-26T10:23:05+00:00
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    Answer:

    128 numbers are divisible by 7 that leave remainder 0

  2. thuhuong
    0
    2021-08-26T10:23:17+00:00
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    Answer:

    128

    Step-by-step explanation:

    Let’s find the first 3 digit number divisible by 7.

    7(12)=84

    7(13)=91

    7(14)=98

    7(15)=105

    So our first 3 digit number divisible by 7 is 105.

    Let’s figure out the last 3 digit number divisible by 7.

    7(200)=1400

    Skip a lot

    7(150)=1050

    Skip a little more

    7(140)=980

    Skipped too much

    7(145)=1015

    7(144)=1008

    7(143)=1001

    7(142)=994

    So there are 142-15+1 multiples of 7 that are 3 digits long.

    142-15+1

    142-14

    128

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