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$N=\frac{1}{/x-1/+5}$
helppppppppppppppppp $N=\frac{1}{/x-1/+5}$
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helppppppppppppppppp
$N=\frac{1}{/x-1/+5}$
Ladonna
`|x-1|≥0`
`=> |x-1|+5≥5`
`=> N = 1/(|x-1|+5)≤1/5`
Dấu “=” xảy ra `<=> x = 1`
Vậy `Max_N = 1/5 <=> x = 1`
Mít Mít
Đáp án:
Vậy $N_{max}=\dfrac{1}{5}⇔x=1$
Giải thích các bước giải:
Ta có:$|x-1|≥0 ∀x∈Q$
$⇒|x-1|+5≥5 ∀x∈Q$
Do đó:
$\dfrac{1}{|x-1|+5}≥\dfrac{1}{5} $
Dấu $”=”$ xảy ra khi:
$|x-1|=0⇔x-1=0⇔x=1$
Vậy $N_{max}=\dfrac{1}{5}⇔x=1$
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