## Help please !!! At a local Brownsville play production, 420 tickets were sold. The ticket prices varied on the seating arrangements an

Question

Help please !!! At a local Brownsville play production, 420 tickets were sold. The ticket prices varied on the seating
arrangements and cost $8,$10, or $12. The total income from ticket sales reached$3920. If the
combined number of $8 and$10 priced tickets sold was 5 times the number of $12 tickets sold, how many tickets of each type were sold? in progress 0 2 months 2021-08-02T07:55:41+00:00 1 Answers 3 views 0 ## Answers ( ) 1. Answer: n = 12$    x = 8$y = 10$     where n, x, and y are number of tickets

12 n + 8 x + 10 y = 3920     and n + x + y = 420

12n + 8 (x + y) + 2 y = 3920

12 n + 8 (5 n) + 2 y = 3920        since 5 (x + y) = n

52 n + 2 y = 3920   or  y = 1960 – 26 n

Also, n + x + y = 420   or n + 5 n = 420   since x + y = 5 n

n = 70    so 70 of the \$12 were sold

And since y = 1960 – 26 n     we have y = 140 tickets

Now 12 * 70 + 8 x + 140 * 10 = 3920

This gives x = 210 tickets

Check:   210 + 140 + 70 = 420 tickets

Also, 12 * 70 + 210 * 8 + 140 * 10 = 3920