HELP ASAP!! A 41kg girl sits on the edge of a merry-go-round. If she travels at 0.02ms and the radius of her motion is 2.1m, wh

Question

HELP ASAP!!
A 41kg girl sits on the edge of a merry-go-round. If she travels
at 0.02ms and the radius of her motion is 2.1m, what is the centripetal force acting upon her?

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Vodka 1 year 2021-09-04T00:04:17+00:00 1 Answers 1 views 0

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  1. Thunguyet
    0
    2021-09-04T00:06:15+00:00
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    Answer:

    Centripetal force F = 0.0078 N

    Explanation: Given that the

    Mass M = 41 kg

    Velocity V = 0.02 m/s

    Radius r = 2.1 m

    Centripetal force F = MV^2/r

    Substitutes all the parameters into the formula

    F = (41 × 0.02^2)/2.1

    F = ( 41 × 0.0004 )/2.1

    F = 0.0164/2.1

    F = 0.0078 N

    The centripetal force acting upon her is 0.0078 Newton

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