Hellllp meeeeeeeeêeê

$|x-1|+|3y+10|≤0$

mà $|x-1|,|3y+10|≥0$

$→|x+1|+|3y+10|=0$

$→\begin{cases}x+1=0\\3y+10=0\end{cases}$

$→\begin{cases}x=-1\\y=-\dfrac{10}{3}\end{cases}$

Vậy $x=-1;y=-\dfrac{10}{3}$ thì $|x+1|+|3y+10|≤0$