Heat flows into a gas in a piston and work is performed on the gas by its surroundings. The amount of work done is equal to the heat added.

Question

Heat flows into a gas in a piston and work is performed on the gas by its surroundings. The amount of work done is equal to the heat added. In this situation,

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Ngọc Hoa 3 years 2021-08-28T11:03:06+00:00 1 Answers 6 views 0

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    2021-08-28T11:04:47+00:00

    Answer:

    The Internal energy of the gas did not change

    Explanation:

    In this situation the Internal energy of the gas did not change and this is because according the the first law of thermodynamics

    Δ U = Q – W  —— ( 1 )

    Δ U  = change in internal energy

    Q = heat added

    W = work done

    since Q = W.  the value of ΔU  will be = zero   i.e. No change

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