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Heat flows into a gas in a piston and work is performed on the gas by its surroundings. The amount of work done is equal to the heat added.
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Answers ( )
Answer:
The Internal energy of the gas did not change
Explanation:
In this situation the Internal energy of the gas did not change and this is because according the the first law of thermodynamics
Δ U = Q – W —— ( 1 )
Δ U = change in internal energy
Q = heat added
W = work done
since Q = W. the value of ΔU will be = zero i.e. No change