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## he pump in a water tower lifts water with a density of rhow = 1.00 kg/liter from a filtered pool at the bottom of the tower up hT = 32 m to

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he pump in a water tower lifts water with a density of rhow = 1.00 kg/liter from a filtered pool at the bottom of the tower up hT = 32 m to the top of the tower. The water begins at rest in the pool and comes to rest at the top of the tower. The pump is 100% efficient in lifting the water, and it lifts a volume of Vw = 5.2 liters of water up the tower every second. The water tower sits on a hill that is Te = 25 m above sea level. Let gravitational potential energy be zero at ground level.Calculate the power. Pp in Watts, of the pump

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Physics
1 year
2021-08-30T13:49:45+00:00
2021-08-30T13:49:45+00:00 1 Answers
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## Answers ( )

Answer:[tex]\dot W = 356.975 W[/tex]

Explanation:The ideal power of the pump is:

[tex]\dot W = \eta \cdot \rho_{w} \cdot g \cdot \Delta h_{T} \cdot \dot V\\\dot W = (1)\cdot (1 \frac{kg}{L} ) \cdot (9.807 \frac{m}{s^2}) \cdot (32 m – 25 m) \cdot (5.2 \frac{L}{s} )\\\dot W = 356.975 W[/tex]