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Given u = ⟨1, 3⟩, v = ⟨2, 1⟩, and cos(ϴ) = sqrt2/2, where ϴ is the angle between the vectors, what is the scalar projection uv and the dot p
Question
Given u = ⟨1, 3⟩, v = ⟨2, 1⟩, and cos(ϴ) = sqrt2/2, where ϴ is the angle between the vectors, what is the scalar projection uv and the dot product u · v?
uv = 1.41 and u*v = 4.47
uv = 2.24 and u · v = 5.00
uv = 2.24 and u · v = 7.07
uv = 7.07 and u · v = 15.81
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2021-08-22T00:07:21+00:00
2021-08-22T00:07:21+00:00 2 Answers
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Answer:
Step-by-step explanation:
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Answer: B. uv = 2.24 and u · v = 5.00
Step-by-step explanation:
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