Given the equation below, What is the reducing agent? NOTE: Only enter the element symbol. For instance: K, or Cr, or O, or H.

Question

Given the equation below, What is the reducing agent?
NOTE: Only enter the element symbol. For instance: K, or Cr, or
O, or H.
K2Cr2O3 + H2O + S –> SO2 + KOH + Cr2O3

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Khoii Minh 4 years 2021-08-18T22:29:14+00:00 1 Answers 5 views 0

Answers ( )

  1. Thunguyet
    0
    2021-08-18T22:30:55+00:00
    Reply

    Answer:

    Reducing agent – S

    Explanation:

    The equation for the reaction is given as;

    K2Cr2O3 + H2O + S –> SO2 + KOH + Cr2O3

    The balanced equation is given as:

    2K2Cr2O7 + 2H2O + 3S → 3SO2 + 4KOH + 2Cr2O3        

    The reducing agent can be obtained by comparing the oxidation number of the elements. Increase in oxidation number signifies a reducing agent

    K:

    Reactant – 1

    Product – 1

    Cr

    Reactant – +2

    Product – +3

    O

    Reactant –   -2

    Product –    -2

    H

    Reactant – +1

    Product – +1

    S

    Reactant – O

    Product – +4

    S has an increase in oxidation number hence it is the reducing agent.

    Although Cr has an increase in oxidation number, it occurs as a compound.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )