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## Given D,E, and F are collinear points, E is between D and F, DE is six times the length of EF, and DF=84 units, find the length of seg

Question

Given D,E, and F are collinear points, E is between D and F,

DE is six times the length of EF, and DF=84 units, find the length of segment DE.

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Mathematics
1 year
2021-09-03T16:09:47+00:00
2021-09-03T16:09:47+00:00 1 Answers
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## Answers ( )

Answer:## 72 units

Step-by-step explanation:Given D,E, and F are collinear points and E is between D and F, then the expression DE + EF = DF….

1is trueIf DE is six times the length of EF, then;

DE = 6DF

DF = DE/6 …..

2Substitute equation 2 into 1;

DE + EF = DF

DE + DE/6 = DF

find the LCM

(6DE+DE)/6 = DF

cross multiply

6DE+DE = 6DF

7DE = 6DF

Given DF = 84units

7DE = 6(84)

7DE = 504

Divide both sides by 7

7DE/7 = 504/7

DE = 72Hence the length of segment DE is 72units