Giúp mk vs mk đg cần gấp ạ cac bn lm đc bao nh câu thì lm, ít nhất 2-3 câu nhé

Giải thích các bước giải:

Ta có:

\(\begin{array}{l}
g,\\
{a^3} – {a^2} – a + 1\\
 = \left( {{a^3} – {a^2}} \right) – \left( {a – 1} \right)\\
 = {a^2}\left( {a – 1} \right) – \left( {a – 1} \right)\\
 = \left( {a – 1} \right)\left( {{a^2} – 1} \right)\\
 = \left( {a – 1} \right)\left( {a – 1} \right)\left( {a + 1} \right)\\
 = {\left( {a – 1} \right)^2}.\left( {a + 1} \right)\\
h,\\
{m^2} + am + ay – {y^2}\\
 = \left( {{m^2} – {y^2}} \right) + \left( {am + ay} \right)\\
 = \left( {m – y} \right)\left( {m + y} \right) + a\left( {m + y} \right)\\
 = \left( {m + y} \right).\left( {m – y + a} \right)\\
i,\\
3xy + {y^2} – 3x – 1\\
 = \left( {3xy – 3x} \right) + \left( {{y^2} – 1} \right)\\
 = 3x\left( {y – 1} \right) + \left( {y – 1} \right)\left( {y + 1} \right)\\
 = \left( {y – 1} \right)\left( {3x + y + 1} \right)\\
k,\\
{x^3} – x{y^2} + {x^2}y – {y^3}\\
 = \left( {{x^3} + {x^2}y} \right) – \left( {x{y^2} + {y^3}} \right)\\
 = {x^2}\left( {x + y} \right) – {y^2}\left( {x + y} \right)\\
 = \left( {x + y} \right).\left( {{x^2} – {y^2}} \right)\\
 = {\left( {x + y} \right)^2}.\left( {x – y} \right)\\
l,\\
{a^3} – ma – mb + {b^3}\\
 = \left( {{a^3} + {b^3}} \right) – \left( {ma + mb} \right)\\
 = \left( {a + b} \right)\left( {{a^2} – ab + {b^2}} \right) – m\left( {a + b} \right)\\
 = \left( {a + b} \right).\left( {{a^2} – ab + {b^2} – m} \right)
\end{array}\)