a.4x = 64 = 64:4 = 16 b.2x + 2 = 8 = 8 – 2 – 2 = 4 = $2^{4+2}$ c.(x – $1^{12}$) = (x – $1$)$^{11}$ Reply
tìm x biết .
4^x=64⇒x=3 vì 3.3.3=64
2^x+2=8⇒x=1 vì 2^1+2 = 2.2.2=8
a.4x = 64 = 64:4 = 16
b.2x + 2 = 8 = 8 – 2 – 2 = 4 = $2^{4+2}$
c.(x – $1^{12}$) = (x – $1$)$^{11}$