Giúp mình với ah
Bài 1 : tính
a,(3-2y)^2
b,(3x+5y)^3
c,(6x-3y)^2
d,(3x+y^5
e,(2x-1)^3
f, 8x^3-y^3
Giúp mình với ah Bài 1 : tính a,(3-2y)^2 b,(3x+5y)^3 c,(6x-3y)^2 d,(3x+y^5 e,(2x-1)^3 f, 8x^3-y^3
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Tryphena
Bài 1:
$a)(3-2y)^2_{}$
$⇔4y^2-12y+9_{}$
$b)(3x+5y)^3_{}$
$⇔(3x)^3+3.(3x)^2.5y+3.3x(5y)^2+(5y)^3_{}$
$⇔27x^3+3.9x^2.5y+3.3x.25y^2+125y^3_{}$
$⇔27x^3+135x^2y+225xy^2+125y^3_{}$
$+)Nếu_{}$ $(3x+5y)^2_{}$ $thì{}:$
$⇔(3x)^2+2.3x.5y+(5y)^2_{}$
$⇔9x^2+30xy+25y^2_{}$
$c)(6x-3y)^2_{}$
$⇔(6x)^2-2.6x.3y+(3y)^2_{}$
$⇔36x^2-36xy+9y^2_{}$
$d)(3x+y)^2_{}$
$⇔(3x)^2+2.3xy+y^2_{}$
$⇔9x^2+6xy+y^2_{}$
$e)(2x-1)^3_{}$
$⇔(2x)^3-3.(2x)^2.1+3.2x.1^2-1^3_{}$
$⇔8x^3-3.4x^2.1+3.2x.1-1_{}$
$⇔8x^3-12x^2+6x-1_{}$
$d)8x^3-y^3_{}$
$⇔2^3x^3-y^3_{}$
$⇔(2x)^3-y^3_{}$
$⇔(2x-y).[(2x)^2+2xy+y^2 ] _{}$
$⇔(2x-y)(4x^2+2xy+y^2)_{}$
King
Đáp án:
Giải thích các bước giải:
`a)(3-2y)^2`
`=3^2-2.3.2y+(2y)^2`
`=9-12y+4y^2
`b)(3x+5y)^3`
`=(3x)^3+3.(3x)^2.5y+3.3x.(5y)^2+(5y)^3`
`=27x^3+135x^2y+225xy^2+125y^3`
`c)(6x-3y)^2`
`=(6x)^2-2.6x.3y+(3y)^2
`=36x^2-36xy+9y^2`
`d)(3x+y)^5`
`=(3x)^5+5.(3x)^4.y+10.(3x)^3.y^2+10.(3x)^2.y^3+5.3x.y^4+y^5`
`=243x^5+405x^4y+270x^3y^2+90x^2y^3+15xy^4+y^5`
`e)(2x-1)^3`
`=(2x)^3-3.(2x)^2.1+3.2x.1^2-1^3`
`=8x^4-12x^2+6x-1`
`f)8x^3-y^3`
`=(2x)^3-y^3`
`=(2x-y)[(2x)^2+2x.y+y^2]`
`=(2x-y)(4x^2+2xy+y^2)`