Giúp mình với ạ!!! Thankssssss

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Giúp mình với ạ!!!
Thankssssss
giup-minh-voi-a-thankssssss

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Calantha 1 year 2020-11-16T04:59:36+00:00 1 Answers 51 views 0

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  1. Eirian
    0
    2020-11-16T05:01:24+00:00
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    `a)`

    `T_{vec{v}} (M) = M’ (2 + 3; – 4 + 0)`

    `=> M’ (5; -4)`

    `b)` 

    Vì `T_{vec{v}} (Δ) = Δ’`

    `=> Δ’` có dạng: `-2x + 3y + c = 0`

    Lấy điểm `A (1; 0) ∈ Δ`

    `=> T_{vec{v}} (A) = A’ (1 + 2; -4 + 0)`

    `=> A’ = (3; -4)`

    `=> A’ ∈ Δ’`

    `=> (-2).3 + 3.(-4) + c = 0`

    `<=> c = 18`

    `=> Δ’: -2x + 3y + 18 = 0`

    `c)` Ta có

    `(C)` \(\left\{ \begin{array}{l}I(2; -3)\\R = \sqrt{2^2 + (-3)^2 + 1} = \sqrt{14}\end{array} \right.\)

    Gọi `T_{vec{v}} (I) = I’`

    `=> I’ (2 + 2; -4 + 3) = (4; -1)`

    `=> (C’)` có: \(\left\{ \begin{array}{l}I(4; -1)\\R = \sqrt{14}\end{array} \right.\)

    `=> (C’): (x – 4)² + (y + 1)² = 14`

    `d)` 

    Ta có:

    `T_{vec{v}} (A) = A’`

    `=> A (- 1 – 2; 8 + 4) = (-3; 12)`

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )