Giúp mình bài này với ạ

Đáp án:

 $\dfrac{72}{5}\\$

Giải thích các bước giải:

 $h) \dfrac{\left ( \dfrac{2}{3} \right )^3.\left ( -\dfrac{3}{4} \right )^2.(-1)^{2993}}{\left ( \dfrac{2}{5} \right )^2.\left ( \dfrac{-5}{12} \right )^3}$
$=\dfrac{ \dfrac{2^3}{3^3} .\dfrac{3^2}{4^2} .(-1)}{\dfrac{2^2}{5^2}.\dfrac{(-5)^3}{12^3} }$
$=\dfrac{ \dfrac{2^3.3^2}{3^3.2^4}.(-1)}{\dfrac{2^2.(-1).5^3}{5^2.(2^2.3)^3}}$
$=\dfrac{ \dfrac{-1}{6}}{\dfrac{-2^2.5}{2^6.3^3}} $

$=\dfrac{ \dfrac{-1}{6}}{\dfrac{-5}{2^4.3^3}} $
$=\dfrac{-1}{6}.\dfrac{2^4.3^3}{-5}\\
=\dfrac{8.9}{5}\\
=\dfrac{72}{5}\\$