Giúp mik với mn ơi,thanks nhìu

Bài 3:

a. `1/(64)=(1/8)^2`

`1/(64)=(1/4)^3`

`1/(64)=(1/2)^6`

b. `(x-1)^2=1/(64)`

 `⇒|x-1|=1/8`

$⇒\left[ \begin{array}{l}x-1=\frac{1}{8}\\x-1=-\frac{1}{8}\end{array} \right.⇒\left[ \begin{array}{l}x=\frac{9}{8}\\x=\frac{7}{8}\end{array} \right.$

Vậy `x=9/8` hoặc `x=7/8`

`(2x+1)^3=1/(64)`

`⇒(2x+1)^3=(1/4)^3`

`⇒2x+1=1/4`

`⇒2x=-3/4`

`⇒x=-3/8`

Vậy `x=-3/8`

Bài 4:

a. $2^4=(2^2)^2=4^2$

$8^2=(2^3)^2=2^6=4^3$

$2^{10}=(2^2)^5=4^5$

$256=4.64=4.4^3=4^4$

b. Ta có: $256=4^4=(2^2)^4=2^8$

Vì $2^8<2^{10}$

$⇒2^{10}>256$

c. $4^x=2^4$

$⇒(2^2)^x=2^4$

$⇒2^{2x}=2^4$

$⇒2x=4$

$⇒x=2$

Vậy $x=2$

$4^{2x+1}=8^2$

$⇒4^{2x+1}=4^3$

$⇒2x+1=3$

$⇒2x=2$

$⇒x=1$

Vậy $x=1$.