giup mik bai 1 vs may ban eiiiiiii

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1. a) $(x+1)^3=x^3+3x^2.1+3x.1^2+1^3=x^3+3x^2+3x+1$

   b) $(2x+3)^2=(2x)^3+3.(2x)^2.3+3.2x.3^2+3^3=8x^3+36x^2+54x+27$

   c) $(x+\dfrac{1}{2})^3=x^3+3.x^2.\dfrac{1}{2}+3.x.(\dfrac{1}{2})^2+(\dfrac{1}{2})^3$

   $=x^3+\dfrac{3}{2}x^2+\dfrac{3}{4}x+\dfrac{1}{8}$

   d) $(x^2+2)^3=(x^2)^3+3.(x^2)^2.2+3.x.2^2+2^3=x^6+6x^4+12x+8$

   e) $(2x+3y)^3=(2x)^3+3.(2x)^2.3y+3.2x.(3y)^2+(3y)^3$

   $=8x^3+36x^2y+54xy^2+27x^3$

   f) $(\dfrac{1}{2}y+x^2)^3=(\dfrac{1}{2}y)^3+3.(\dfrac{1}{2}y)^2.x^2+3.\dfrac{1}{2}y.x^2+(x^2)^3$

   $=\dfrac{1}{8}y^3+\dfrac{3}{4}x^2y^2+\dfrac{3}{2}x^2y+x^6$

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2. $\text{ trong hình ạ}$

    

   

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