Giải thích các bước giải: d)$\frac{128}{2^{2}.n}$=2 ⇒$\frac{128}{4.n}$=2 ⇒$\frac{32}{n}$=2 ⇒n=32:2 ⇒n=16 c)$\frac{2^{62}.27^{27}}{3^{79}.4^{30}}$- $\frac{0,36^{6}}{0,18^{5}}$ =$\frac{2^{62}.(3^{3})^{27}}{3^{79}.(2^{2})^{30}}$ =$\frac{2^{62}.3^{81}}{3^{79}.2^{60}}$-$\frac{(0,18.2)^{6}}{0,18^{5}}$ = $\frac{2^{2}.3^{2}}{1.1}$- $\frac{0,18^{6}.2^{6}}{0,18^{5}}$ = 4.9-$\frac{0,18.64}{1}$ =36-11,12 =24,88 Reply
Giải thích các bước giải:
d)$\frac{128}{2^{2}.n}$=2
⇒$\frac{128}{4.n}$=2
⇒$\frac{32}{n}$=2
⇒n=32:2
⇒n=16
c)$\frac{2^{62}.27^{27}}{3^{79}.4^{30}}$- $\frac{0,36^{6}}{0,18^{5}}$
=$\frac{2^{62}.(3^{3})^{27}}{3^{79}.(2^{2})^{30}}$
=$\frac{2^{62}.3^{81}}{3^{79}.2^{60}}$-$\frac{(0,18.2)^{6}}{0,18^{5}}$
= $\frac{2^{2}.3^{2}}{1.1}$- $\frac{0,18^{6}.2^{6}}{0,18^{5}}$
= 4.9-$\frac{0,18.64}{1}$
=36-11,12
=24,88