giúp e vs ạ aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

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1. a, $xA⊥m$
   $yB⊥m$
   $⇒xA//yB$

   b, Gọi góc $B$ cho sẵn độ là $B1$
   $B1+B2=180^o$($2$ góc kề bù)

   $⇒76^o+B2=180^o$
   $⇒B2=180^o-76^o=104^o$
   $xA//yB$
   $⇒A3=B1=76^o$(so le trong)

   $A3=A1=76^o$($2$ góc đối đỉnh)

   $xA//yB$

   $⇒B2=A4=104^o$(so le trong)

   $A4=A2=104^o$($2$ góc đối đỉnh)

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