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gas LA of certain mass occupies a volume of 650 cm3 under a pressure of 760mmHg. Calculate the pressure under which the volum
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Answers ( )
Answer:
844.4cm³
Explanation:
Using Boyle’s law equation;
P1V1 = P2V2
Where;
P1 = initial pressure (mmHg)
P2 = final pressure (mmHg)
V1 = initial volume (cm³)
V2 = final volume (cm³)
According to the information in this question,
V1 = 650cm³
P1 = 760mmHg
P2 = ?
V2 = 10% reduction of V1
10% of 650 = 10/100 × 650
65
V2 = 650 – 65 = 585cm³
Using P1V1 = P2V2
P2 = P1V1 ÷ V2
P2 = (760 × 650) ÷ 585
P2 = 494000 ÷ 585
P2 = 844.44
final pressure (P2) = 844.4cm³