gas LA of certain mass occupies a volume of 650 cm3 under a pressure of 760mmHg. Calculate the pressure under which the volum

Question

gas
LA of certain mass occupies a volume of 650 cm3 under
a pressure of 760mmHg. Calculate the pressure under which
the volume of the
gas
cent
of its original volume
will be reduced by 10 per​

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Tài Đức 2 weeks 2021-09-04T11:21:49+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-09-04T11:23:22+00:00

    Answer:

    844.4cm³

    Explanation:

    Using Boyle’s law equation;

    P1V1 = P2V2

    Where;

    P1 = initial pressure (mmHg)

    P2 = final pressure (mmHg)

    V1 = initial volume (cm³)

    V2 = final volume (cm³)

    According to the information in this question,

    V1 = 650cm³

    P1 = 760mmHg

    P2 = ?

    V2 = 10% reduction of V1

    10% of 650 = 10/100 × 650

    65

    V2 = 650 – 65 = 585cm³

    Using P1V1 = P2V2

    P2 = P1V1 ÷ V2

    P2 = (760 × 650) ÷ 585

    P2 = 494000 ÷ 585

    P2 = 844.44

    final pressure (P2) = 844.4cm³

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