g you slide a toy car to see the loop the loop physics. the radius of the loop 0.5 m. The acceleration of gravity what is the minimal heigh

Question

g you slide a toy car to see the loop the loop physics. the radius of the loop 0.5 m. The acceleration of gravity what is the minimal height h you need to release the car from so that it makes the loop

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Jezebel 3 years 2021-08-05T23:41:30+00:00 1 Answers 13 views 0

Answers ( )

  1. kiet
    0
    2021-08-05T23:42:51+00:00
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    Answer:

     h = 1.5 m

    Explanation:

    This exercise must be solved using the concepts of energy.

    Starting point. Place where the car leaves

              Em₀ = U = m g h

    Final point. Highest part of the loop, r = 2R

              Em_f = K + U

              Em_f = ½ m v² + mg (2R)

    the energy is preserved

              Em₀ = Em_f

              m g h = ½ m v² + m g 2R               (1)

    the car must have a minimum velicate so that it does not fall, let’s use Newton’s second law.

             ∑ F = m a

             N + W = m a

    acceleration is centripetal

              a = v²/ r

    the normal is the reaction of the surface to the support of the car, as the speed decreases, the normal decreases until reaching zero

             0 + m g = m v² / r

             v² =  rg

    we substitute

            v² = 2Rg

    we substitute in equation 1

              g h = ½ 2Rg + 2Rg

              h = 3R

    let’s calculate

              h = 3 0.5

              h = 1.5 m

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