g to generate electricity, solar panels typically absorb visible light. How many photons of light with a frequency of 5045×10 14 hz does a s

Question

g to generate electricity, solar panels typically absorb visible light. How many photons of light with a frequency of 5045×10 14 hz does a solar panel absorb to create 360 kj

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Mít Mít 6 months 2021-07-15T20:20:37+00:00 1 Answers 6 views 0

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    2021-07-15T20:22:21+00:00

    Answer:

    the number of photons absorbed by the solar panel is 1.08 x 10²¹

    Explanation:

    Given;

    frequency of each photon absorbed, f = 5045 x 10¹⁴ Hz

    energy to be created by the solar panel, E = 360 kJ = 360,000 J

    The energy of each photon absorbed is calculated as;

    E_{photon} = hf\\\\where;\\\\h \ is \ Planck's \ constant = 6.626 \times 10^{-34}  \ Js\\\\E_{photon}  = (6.626 \times 10^{-34} )(5045 \times 10^{14})\\\\E_{photon} = 3.343 \times 10^{-16} \ J

    let the number of photons absorbed = n

    n(E_{photon}) = 360,000 \ J\\\\n = \frac{360,000 \ J}{3.343 \times 10^{-16} \ J} \\\\n = 1.08 \times 10^{21} \ photons

    Therefore, the number of photons absorbed by the solar panel is 1.08 x 10²¹

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