g How many rpm would a 25 m diameter Ferris wheel need to travel if a 75 kg person were to experience an effective weight of 810 N at the lo

Question

g How many rpm would a 25 m diameter Ferris wheel need to travel if a 75 kg person were to experience an effective weight of 810 N at the lower-most point of the ride

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Sapo 6 months 2021-08-13T01:50:45+00:00 1 Answers 7 views 0

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    2021-08-13T01:51:47+00:00

    Answer:

    2.52 rpm

    Explanation:

    given that

    diameter of the wheel, d = 25 m

    Mass of the person, m = 75 kg

    Weight experienced, N = 810 N

    Since diameter is 25, radius then is 25/2 = 12.5 m

    We all know that,

    v = rw

    Also, the passengers weight is equal to the centripetal acceleration, and thus

    mg = mv²/r

    Substitute for v, we have

    mg = m/r * (rw)²

    mg = mr²w²/r

    g = rw²

    If we make w the subject of formula, we have

    w² = g/r

    w = √(g/r)

    mg = 810

    75 * g = 810

    g = 810 / 75

    g = 1.08 m/s²

    w = √(g/r)

    w = √(1.08 / 12.5)

    w = √0.0864

    w = 0.294 rad/s

    Since the question asked us in rpm, we convert to rpm

    0.294 * (60 / 2π)

    2.52 revolution per minute.

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