g how many moles of NO are produced if 2.5 mol of O2 react completely with 4.0 mol of NH3 (molar mass of NO

g how many moles of NO are produced if 2.5 mol of O2 react completely with 4.0 mol of NH3 (molar mass of NO

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  1. Answer:

    2 moles of NO

    Explanation:

    Our reaction is:

    4NH₃ + 5O₂  →   6H₂O  +  4NO  

    4 moles of ammonia react to 5 moles of oxygen in order to produce 6 moles of water and 4 moles of NO

    We need to determine the limiting reactant:

    Ratio is 4:5, As 4 moles of ammonia react to 5 moles of oxygen and we have 4 moles, we definetely need 5 moles, but the problem is, we only have 2.5 moles of O₂. Oxygen is the limting reagent.

    5 moles of O₂ produce 4 moles of NO, according to stoichiometry

    2.5 moles of O₂ may produce (2.5 . 4) / 5 = 2 moles of NO

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