g A simple pendulum (consisting of a point mass suspended by a massless string) on the surface of the earth has a period of 1.00 s. On a dis

Question

g A simple pendulum (consisting of a point mass suspended by a massless string) on the surface of the earth has a period of 1.00 s. On a distant planet, a pendulum of identical length but twice the mass is found to have the same period. What is true about the acceleration due to gravity on the distant planet? [Assume both pendulums operate free of any friction or air resistance force]

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Tài Đức 6 months 2021-07-20T12:41:45+00:00 1 Answers 6 views 0

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  1. mit
    0
    2021-07-20T12:43:34+00:00
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    Answer:

    Explanation:

    The formula for time period of a pendulum is given as follows :

    T = 2π\sqrt{\frac{l}{g} }

    l is length of pendulum and g is acceleration due to gravity .

    So time period of pendulum  is not dependent on the mass of the pendulum . If time period is same and length is also the same then acceleration due to gravity will also be the same . Hence the acceleration due to gravity at distant planet will be same as that on the earth.

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