g(1)= -2 g(2)= 6 g(n)=g(n−2)⋅g(n−1)​ Find g(3). Show me the solutions and calculations.​

g(1)= -2

g(2)= 6

g(n)=g(n−2)⋅g(n−1)​

Find g(3). Show me the solutions and calculations.​

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  1. Answer:

    g(3) is -12

    Step-by-step explanation:

    Given that

    g(1)= -2

    g(2)= 6

    g(n)=g(n−2)⋅g(n−1)​

    Now the g(3) is

    g(3) = g(3 – 2) . g(3 – 1)

    = g(1).g(2)

    = (-2) (6)

    = -12

    Hence, g(3) is -12

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