Function f (x) = 25x/x + 3 has a discontinuity at x = –3. What are Limit of f (x) as x approaches negative 3 minus and Limit of f (x) as x a

Question

Function f (x) = 25x/x + 3 has a discontinuity at x = –3. What are Limit of f (x) as x approaches negative 3 minus and Limit of f (x) as x approaches negative 3 plus?

in progress 0
Thu Thủy 4 years 2021-08-01T16:44:01+00:00 2 Answers 9 views 0

Answers ( )

  1. Sapo1
    0
    2021-08-01T16:45:03+00:00
    Reply

    Answer:

    x approaches negative 3 to the right: lim_{x\to -3^{+}}=-\infty

    x approaches negative 3 to the left: lim_{x\to -3^{-}}=\infty

    Step-by-step explanation:

    The function we have is:

    f(x)=\frac{25x}{x+3}

    We have an asymptote at x = -3.

    The limit of the function when x approaches negative 3 to the right will be:

    lim_{x\to -3^{+}}=\frac{25x}{(-3)+3}=-\infty

    It is because the function is decreasing from right to left.

    And the limit of the function when x approaches negative 3 to the left will be:

    lim_{x\to -3^{-}}=\frac{25x}{(-3)+3}=\infty

    It is because the function is decreasing from left to right.

    I hope it helps you!

  2. thuthao
    0
    2021-08-01T16:45:31+00:00
    Reply

    Answer: C

    Step-by-step explanation:

    Edge

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )