For the unbalanced reaction below, calculate how many grams of oxygen form when 2.72 g of potassium chlorate completely reacts.

Question

For the unbalanced reaction below, calculate how many grams of oxygen form when 2.72 g of potassium chlorate completely reacts.

KClO3(s) –> KCl(s) + O2(g)

in progress 0
Thanh Hà 2 months 2021-07-14T07:40:07+00:00 1 Answers 3 views 0

Answers ( )

    0
    2021-07-14T07:41:16+00:00

    Answer:

    1.06g O2

    Explanation:

    Let’s first balance the equation.

    2KClO3 > 2KCl + 3O2

    We’re going to go from:

    1. Grams of KClO3: 2.72g
    2. to moles, using molar mass of KClO3: 122.5g/mol
    3. We’ll convert to O2 using a mole ratio, where we have 2 mols of KClO3 to 3 mols of O2.
    4. To grams of O2 using molar mass: 32g/mol

    2.72g x (\frac{1 mol}{122.5g} * \frac{3 mol O2}{2 mol KClO3} * \frac{32g}{1 mol} )= 1.06 g

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )