For the reaction Cu2S(s)⇌2Cu+(aq)+S2−(aq)Cu2S(s)⇌2Cu+(aq)+S2−(aq), the equilibrium concentrations are as follows: [Cu+]=1.0×10−5[Cu+]=1.0×10

Question

For the reaction Cu2S(s)⇌2Cu+(aq)+S2−(aq)Cu2S(s)⇌2Cu+(aq)+S2−(aq), the equilibrium concentrations are as follows: [Cu+]=1.0×10−5[Cu+]=1.0×10−5 M, [S2−]=1.0×10−2[S2−]=1.0×10−2 M. The equilibrium constant is:

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Ngọc Diệp 5 months 2021-08-10T01:56:31+00:00 1 Answers 6 views 0

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    2021-08-10T01:58:05+00:00

    Answer:

    1×10⁻¹²

    Explanation:

    • Cu₂S(s) ⇌ 2Cu⁺(aq) + S²⁻(aq)

    At equilibrium:

    • [Cu⁺] = 1.0×10⁻⁵ M
    • [S²⁻] = 1.0×10⁻² M

    The equilibrium constant for the the reaction can be written as:

    • Keq = [Cu⁺]² * [S²⁻]

    [Cu⁺] is squared because it has a stoichiometric coefficient of 2 in the reaction. Cu₂S has no effect on the constant because it is a solid.

    Now we can calculate the equilibrium constant:

    • Keq = (1.0×10⁻⁵)² * 1.0×10⁻² = 1×10⁻¹²

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )