For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser pointer (λ=680nm

Question

For a demonstration, a professor uses a razor blade to cut a thin slit in a piece of aluminum foil. When she shines a laser pointer (λ=680nm) through the slit onto a screen 5.5 m away, a diffraction pattern appears. The bright band in the center of the pattern is 8.0 cm wide. What is the width of the slit?

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Orla Orla 4 years 2021-08-20T09:49:34+00:00 2 Answers 181 views 0

Answers ( )

  1. RobertKer
    0
    2021-08-20T09:50:46+00:00
    Reply

    Answer:

    width of slit(a)≅ 0.1mm

    Explanation:

    Wave length of laser pointer =λ = 685 nm

    Distance between screen and slit = L = 5.5 m

    Width of bright band = W=8.0cm=0.08m

    width of slit=a

    recall the formula;

    W=(2λL)/a

    a=2λL/W

    a=(2 *685*10⁻⁹*5.5m)/0.08m

    a=7535*10⁻⁹/0.08

    a=94187.5 *10⁻⁹

    a=0.0000941875m

    a=0.0941875mm

    a≅0.1mm

  2. Ben
    0
    2021-08-20T09:50:59+00:00
    Reply

    Answer:

    The wide of silt is a=93.5×10⁻⁶m

    Explanation:

    Given data

    Wavelength λ=680 nm

    Length L=5.5 m

    Width w=8.0 cm

    To find

    Width of slit a

    Solution

    A single slit of width a has a bright central maximum of width

    ω=2λL/a

    a=2λL/ω

    Substitute the given values

    a=\frac{2*(680*10^{-9}m)5.5m}{0.08m} \\a=93.5*10^{-6}m

    The wide of silt is a=93.5×10⁻⁶m

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