For a body falling freely from rest​ (disregarding air​ resistance), the distance the body falls varies directly as the square of the time.

Question

For a body falling freely from rest​ (disregarding air​ resistance), the distance the body falls varies directly as the square of the time. If an object is dropped from the top of a tower 490 ft high and hits the ground in 7 ​sec, how far did it fall in the first 5 ​sec?

in progress 0
Yến Oanh 1 week 2021-09-04T17:53:00+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-04T17:54:43+00:00

    Explanation:

    Below is an attachment containing the solution.

    0
    2021-09-04T17:54:44+00:00

    Answer:

    The answer to the question is

    The object would fall 57.625 m in the first 5 seconds

    Explanation:

    To solve the question, we note that

    the height of fall = 490 ft = ‪149.352‬ m

    Time to touch the ground = 7 seconds

    We are required to find out how far the object falls in the first 5 seconds

    We apply the relation

    S = u·t + 0.5×g·t ² = We then have

    ‪149.352‬ = U×7+0.5*9.81*49 From where u = -13 m/s

    Therefore to find how far it falls in the first 5 seconds, we have

    -13*5 + 0.5*9.81*25 = 57.625 m

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )