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## For a body falling freely from rest (disregarding air resistance), the distance the body falls varies directly as the square of the time.

Question

For a body falling freely from rest (disregarding air resistance), the distance the body falls varies directly as the square of the time. If an object is dropped from the top of a tower 490 ft high and hits the ground in 7 sec, how far did it fall in the first 5 sec?

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Physics
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2021-09-04T17:53:00+00:00
2021-09-04T17:53:00+00:00 2 Answers
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## Answers ( )

Explanation:

Below is an attachment containing the solution.

Answer:The answer to the question is

The object would fall 57.625 m in the first 5 seconds

Explanation:To solve the question, we note that

the height of fall = 490 ft = 149.352 m

Time to touch the ground = 7 seconds

We are required to find out how far the object falls in the first 5 seconds

We apply the relation

S = u·t + 0.5×g·t ² = We then have

149.352 = U×7+0.5*9.81*49 From where u = -13 m/s

Therefore to find how far it falls in the first 5 seconds, we have

-13*5 + 0.5*9.81*25 = 57.625 m