Find two positive consecutive integers such that the square of the first added to three times the second is 24

Question

Find two positive consecutive integers such that the square of the first added to three times the second is 24

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Philomena 6 months 2021-07-16T10:43:34+00:00 1 Answers 4 views 0

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    2021-07-16T10:45:24+00:00

    Answer:

    3 and 5

    Step-by-step explanation:

    Let the two consecutive odd integers be x and x + 2.

    Now,

    The given statement is

    x^2 + 3 \times (x+2)=24\\x^2 + 3x+6-24 = 0 \\x^2 + 3x-18 = 0\\x^2+6x-3x-18=0\\x(x+6)-3(x+6)=0\\(x-3)(x+6)=0\\x=3,-6

    Taking x=3.

    Hence, two consecutive odd integers are 3 and 5.

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )